HEGP104 — Quadrilaterals
Complete Answers to the
Mathematical Problems
This guide answers the
mathematical problems, construction tasks, angle questions, activities, and
“Figure it Out” exercises in the attached Class 8 chapter.
1. Rectangle and square
investigations
Problem 1. A rectangle has
one diagonal of length 8 cm. What is the length of the other diagonal?
The diagonals of a
rectangle are equal. Therefore, the other diagonal is 8 cm.
Problem 2. Where do the
diagonals of a rectangle intersect?
The diagonals of a
rectangle bisect each other. Therefore, they intersect at their common
midpoint. Since each diagonal is 8 cm, each half-diagonal is 4 cm.
Problem 3. What angle must
the diagonals of a rectangle make with each other?
There is no single fixed
angle. The diagonals of a rectangle are equal and bisect each other, but the
angle between them depends on the rectangle’s length and breadth. They are
perpendicular only when the rectangle is a square.
Problem 4. If equal
diagonals bisect each other at any angle, what quadrilateral is formed?
A quadrilateral whose
diagonals are equal and bisect each other is a rectangle.
If the angle between the diagonals is 90°, it is a square.
Problem 5. If one angle
between the diagonals is (x), what are the four angles at their intersection?
The four angles are
[ x,\quad x,\quad
180^\circ-x,\quad180^\circ-x. ]
For example, if one angle
is 60°, the four angles are 60°, 120°, 60°, and 120°.
Problem 6. What is the value
of each base angle in the isosceles triangle formed by two half-diagonals?
If the vertex angle is (x),
the two equal base angles are
[
\frac{180^\circ-x}{2}=90^\circ-\frac{x}{2}. ]
These angles show that the
resulting quadrilateral has four right angles and is therefore a rectangle.
Problem 7. What additional
properties do the diagonals of a square have?
The diagonals of a square
are equal, bisect each other, and intersect at right angles. They also bisect
the angles of the square. Thus, if one diagonal is 8 cm, the other is also 8
cm, their intersection is the midpoint of both, and the angle between them is
90°.
2. Figure it Out: rectangles
and diagonals
Question 1. Find the
remaining angles inside the rectangles.
(i) Rectangle ABCD
Using the given 30° angle
and the fact that a rectangle has right angles:
[ \angle ABD=30^\circ, ] [
\angle CAD=60^\circ, ] [ \angle ADB=60^\circ, ] [ \angle BDC=30^\circ, ] [
\angle ACD=30^\circ, ] [ \angle ACB=60^\circ. ]
(ii) Rectangle PQRS
Using the given 110° angle,
vertically opposite angles, supplementary adjacent angles, and the
equal-diagonal property:
[ \angle POS=110^\circ, ] [
\angle QOP=70^\circ, ] [ \angle ROS=70^\circ, ] [ \angle OQR=35^\circ, ] [
\angle ORQ=35^\circ, ] [ \angle OQP=55^\circ, ] [ \angle OPQ=55^\circ, ] [
\angle ORS=55^\circ, ] [ \angle OSR=55^\circ. ]
Question 2. Construct a
quadrilateral whose diagonals are equal, 8 cm long, bisect each other, and
intersect at 30°, 40°, 90°, or 140°.
The construction is the
same in every case:
1
Draw (AB=8) cm.
2
Mark its midpoint
(O), so (AO=OB=4) cm.
3
At (O), construct
the required angle with one ray along (OB): 30°, 40°, 90°, or 140°.
4
On the new ray
and its opposite ray, mark (OC=OD=4) cm.
5
Join (A-C),
(C-B), (B-D), and (D-A).
The resulting quadrilateral
is a rectangle in all four cases. For the 90° case,
it is a square.
Question 3. A circle has two
perpendicular diameters (PL) and (AM). What is quadrilateral APML?
All four vertices lie on
the circle, the diagonals are diameters of equal length, they bisect each other
at the centre, and they are perpendicular. Therefore, APML
is a square.
Question 4. How can two
equal sticks and a thread be used to make an exact right angle?
Place the two equal sticks
so that their midpoints coincide. Treat them as the diagonals of a
quadrilateral. Join their four endpoints with a thread. The diagonals are equal
and bisect each other, so the quadrilateral is a rectangle. Every rectangle has
right angles; therefore, the angle at each vertex is exactly 90°.
Question 5. Can opposite
sides being parallel and equal be used as the definition of a rectangle?
No. A quadrilateral with
both pairs of opposite sides parallel and equal is a parallelogram,
but it need not have right angles. A slanted parallelogram is not a rectangle.
A rectangle is a parallelogram with four right angles.
3. Parallelograms and
rhombuses
Problem 6. What are the main
properties of a parallelogram?
In a parallelogram:
[ AB\parallel CD,\qquad
AD\parallel BC, ]
opposite sides are equal,
opposite angles are equal, adjacent angles are supplementary, and the diagonals
bisect each other.
Problem 7. How can a
parallelogram with diagonals 7 cm and 5 cm intersecting at 140° be constructed?
6
Draw (AB=7) cm.
7
Mark its midpoint
(O), so (AO=OB=3.5) cm.
8
At (O), construct
an angle of 140° with (OB).
9
On the two rays
of the new line, mark (OC=OD=2.5) cm.
10 Join (A-C), (C-B), (B-D), and (D-A).
The resulting quadrilateral
is the required parallelogram.
Problem 8. What are the main
properties of a rhombus?
A rhombus has four equal
sides. Its opposite sides are parallel, opposite angles are equal, adjacent
angles add to 180°, and its diagonals bisect one another at right angles. The
diagonals also bisect the angles of the rhombus.
Problem 9. Construct a
rhombus whose diagonals are 4 cm and 5 cm.
11 Draw the longer diagonal (AB=5) cm.
12 Mark its midpoint (O), so (AO=OB=2.5) cm.
13 Through (O), draw a perpendicular line.
14 Mark (OC=OD=2) cm on this perpendicular.
15 Join (A-C), (C-B), (B-D), and (D-A).
The resulting quadrilateral
is the required rhombus.
4. Quadrilateral angle sum
Problem 10. What is the sum
of the interior angles of any quadrilateral?
Draw one diagonal. It
divides the quadrilateral into two triangles. Since each triangle has angle sum
180°,
[
180^\circ+180^\circ=360^\circ. ]
Therefore, the sum of the
interior angles of every simple quadrilateral, including a concave
quadrilateral, is 360°.
5. Kite and trapezium
Problem 11. What is a kite?
A kite is a quadrilateral
with two distinct pairs of equal adjacent sides. If (AB=BC) and (CD=DA), then
ABCD is a kite.
Its symmetry diagonal
bisects the other diagonal at right angles and bisects the angles between the
equal sides.
Problem 12. What is a
trapezium?
A trapezium is a
quadrilateral with at least one pair of parallel opposite sides.
If (PQ\parallel SR), then
the interior angles on each non-parallel side are supplementary:
[ \angle P+\angle
S=180^\circ, ] [ \angle Q+\angle R=180^\circ. ]
Problem 13. What additional
property does an isosceles trapezium have?
An isosceles trapezium has
equal non-parallel sides. Its base angles are equal:
[ \angle U=\angle V, ]
and the other pair of base
angles is also equal. Adjacent angles on a leg remain supplementary.
6. Playing with
quadrilaterals
Activity 1. Join two
equilateral triangles of side 8 cm.
When two equilateral
triangles are joined along a side, the outside boundary is a rhombus. All four outer sides are 8 cm because each comes
from a side of one triangle. The interior angles are 60° and 120° in
alternating order.
Activity 2. Join two
isosceles triangles with sides 8 cm, 8 cm, and 6 cm.
Different joins produce
different quadrilaterals. If the equal 8 cm sides form the outer boundary, the
result has four equal sides and is a rhombus. If
the 6 cm sides or unequal sides form the boundary, the result may be a kite or another quadrilateral depending on the joining
orientation. The side lengths and diagonal arrangement should be checked from
the actual join.
Activity 3. Join two scalene
triangles with sides 6 cm, 9 cm, and 12 cm.
Joining two congruent
scalene triangles along a corresponding side can produce different
quadrilaterals. If the equal corresponding sides form pairs of opposite sides,
a parallelogram may result. If equal sides form adjacent pairs, a kite may
result. In other arrangements, a general quadrilateral is obtained. Each
classification must be justified by checking parallelism, equal sides, or
diagonal properties.
7. Figure it Out: kite,
trapezium, and quadrilateral relationships
Question 1. Find all sides
and angles of the quadrilateral obtained by joining two equilateral triangles
of side 4 cm.
The quadrilateral is a rhombus. All four sides are 4 cm:
[ AB=BC=CD=DA=4\text{ cm}.
]
Its angles alternate
between 60° and 120°:
[ \angle A=\angle
C=60^\circ, ] [ \angle B=\angle D=120^\circ, ]
or the reverse arrangement,
depending on which sides of the triangles are joined.
Question 2. Construct a kite
whose diagonals are 6 cm and 8 cm.
16 Draw one diagonal, say (PQ=6) cm.
17 Construct the perpendicular bisector of (PQ), meeting
it at (T).
18 On the perpendicular bisector, choose points (R) and
(S) so that (RS=8) cm and (T) is the midpoint of (RS). Thus (RT=ST=4) cm.
19 Join (P-R), (R-Q), (Q-S), and (S-P).
The resulting quadrilateral
is the required kite. Its diagonals are perpendicular and have lengths 6 cm and
8 cm.
Question 3. Find the
remaining angles in the trapeziums.
(i) First trapezium
Using supplementary
interior angles on parallel lines:
[ \angle
R=180^\circ-105^\circ=75^\circ, ]
and
[ \angle
S=180^\circ-135^\circ=45^\circ. ]
Thus, the remaining angles
are 75° and 45°.
(ii) Isosceles trapezium
The given top angle is
100°. The other angle on the same leg is
[
180^\circ-100^\circ=80^\circ. ]
Since the trapezium is
isosceles, the corresponding base angle is also 80°. Thus, the remaining angles
are 80° and 80°.
Question 4. Describe the
Venn-diagram relationships among parallelograms, kites, rhombuses, rectangles,
and squares.
The set relationships are:
•
Every square is a
rectangle, a rhombus, a parallelogram, and a kite.
•
Every rectangle
is a parallelogram.
•
Every rhombus is
a parallelogram and a kite.
•
Not every
parallelogram is a rectangle or rhombus.
•
Not every kite is
a rhombus or parallelogram.
(i) What quadrilateral is
both a kite and a parallelogram?
A rhombus
is both a kite and a parallelogram. A square is a special case of this
intersection.
(ii) Can a quadrilateral be
both a kite and a rectangle?
Yes. A square is both a kite and a rectangle because it
has equal adjacent sides and four right angles.
(iii) Is every kite a
rhombus?
No. A rhombus is always a
kite under the chapter’s definition, but a kite need not have all four sides
equal. Therefore, every rhombus is a kite, but not every
kite is a rhombus.
Question 5. If PAIR and RODS
are rectangles, find (\angle IOD).
Since the marked angle
between the diagonal direction and the side is 30°, the corresponding angle at
the intersection of the relevant rectangle sides is also
[ \boxed{\angle
IOD=30^\circ}. ]
8. Constructions and
reasoning
Question 6. Construct a
square with diagonal 6 cm without using a protractor.
20 Draw (AB=6) cm.
21 Construct the perpendicular bisector of (AB), meeting
it at (O).
22 Since (AO=OB=3) cm, mark points (C) and (D) on the
perpendicular line so that (OC=OD=3) cm.
23 Join (A-C), (C-B), (B-D), and (D-A).
The resulting quadrilateral
is a square because its diagonals are equal, bisect each other, and are
perpendicular.
Question 7. CASE is a square
and U, V, W, X are the midpoints of its sides. What type of quadrilateral is
UVWX?
UVWX is a square. If the side of the outer square is (x), then each
side of the inner square is
[\sqrt{\left(\frac{x}{2}\right)^2+\left(\frac{x}{2}\right)^2}
=\frac{x}{\sqrt2}.]
All four sides are equal.
Each angle is 90° because adjacent inner sides have equal slopes with respect
to the outer square’s sides. Hence, UVWX is a square.
Question 8. If a
quadrilateral has four equal sides and one angle of 90°, is it a square?
Yes. Four equal sides make
the quadrilateral a rhombus. In a rhombus, opposite angles are equal and
adjacent angles are supplementary. If one angle is 90°, every adjacent and
opposite angle is also 90°. Therefore, the quadrilateral is a square.
Question 9. What type of
quadrilateral has both pairs of opposite sides equal?
It is a parallelogram. Draw a diagonal. The two triangles formed
have three corresponding equal sides, so they are congruent by SSS.
Corresponding alternate angles are equal, which proves both pairs of opposite
sides are parallel. Hence the quadrilateral is a parallelogram.
Question 10. Is the sum of
the angles of a concave quadrilateral also 360°?
Yes. Draw a diagonal that
divides the concave quadrilateral into two triangles. Each triangle has an
angle sum of 180°:
[
180^\circ+180^\circ=360^\circ. ]
Thus, the angle sum is 360°.
9. True-or-false questions
Question 11(i). A
quadrilateral whose diagonals are equal and bisect each other must be a square.
False. A non-square rectangle also has equal diagonals that
bisect each other. The diagonals must additionally be perpendicular for the
rectangle to be a square.
Question 11(ii). A
quadrilateral having three right angles must be a rectangle.
True. The fourth angle is
[
360^\circ-(90^\circ+90^\circ+90^\circ)=90^\circ. ]
Thus, all four angles are
right angles, so the quadrilateral is a rectangle.
Question 11(iii). A
quadrilateral whose diagonals bisect each other must be a parallelogram.
True. This is a converse property of parallelograms. If the
diagonals of a quadrilateral bisect each other, both pairs of opposite sides
are parallel, so the quadrilateral is a parallelogram.
Question 11(iv). A
quadrilateral whose diagonals are perpendicular to each other must be a
rhombus.
False. A kite can have perpendicular diagonals without all
four sides being equal. A rhombus is one possibility, but perpendicular
diagonals alone are not sufficient.
Question 11(v). A
quadrilateral in which the opposite angles are equal must be a parallelogram.
True. Let the angles be (A,B,A,B). Since their sum is 360°,
[
2A+2B=360^\circ\Rightarrow A+B=180^\circ. ]
The consecutive interior
angles are supplementary, so both pairs of opposite sides are parallel. Hence
it is a parallelogram.
Question 11(vi). A
quadrilateral in which all the angles are equal is a rectangle.
True. Since the angle sum is 360°, each angle is
[ 360^\circ\div4=90^\circ.
]
Therefore, the
quadrilateral is a rectangle.
Question 11(vii). Isosceles
trapeziums are parallelograms.
False. An isosceles trapezium has only one pair of parallel
sides in general. Its non-parallel sides are equal, but they need not be
parallel. Only special cases, such as a rectangle, are both isosceles
trapeziums and parallelograms.
10. Folding and construction
activities
Activity 1. What shape is
formed by the first set of paper creases?
The exact result depends on
the crease pattern shown, but folding a sheet into halves and quarters and
making the indicated triangular crease produces a quadrilateral
whose sides and angles can be identified from the symmetry of the creases.
If the creases are symmetric, the resulting figure is generally a square or
rectangle; if the diagonal crease is included, it may form an isosceles
triangle within the quadrilateral.
Activity 2. How can the
shown crease pattern be made?
Fold the quarter-sheet
along its midpoint lines, then fold the indicated corner to the required points
so that the creases are symmetric. Open the paper and trace the crease
intersections. The desired quadrilateral is obtained from the boundary and the
diagonal crease.
Activity 3. How can a square
be formed from the quarter-sheet?
Fold the quarter-sheet so
that the two adjacent sides are equal and the crease lines meet at right
angles. Align the opposite edges carefully and press the fold. On opening the
paper, the four crease segments form a square.
11. Summary of essential
properties
|
Quadrilateral |
Defining property |
Important
diagonal/angle properties |
|
Rectangle |
Four right angles |
Equal diagonals that
bisect each other |
|
Square |
Four equal sides and four
right angles |
Equal perpendicular
diagonals that bisect angles and each other |
|
Parallelogram |
Both pairs of opposite
sides parallel |
Opposite sides/angles
equal; diagonals bisect each other |
|
Rhombus |
Four equal sides |
Perpendicular diagonals;
diagonals bisect angles |
|
Kite |
Two pairs of equal
adjacent sides |
One diagonal bisects the
other at right angles |
|
Trapezium |
At least one pair of
opposite sides parallel |
Same-side interior angles
are supplementary |
|
Isosceles trapezium |
Non-parallel sides equal |
Base angles are equal |
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